\(\int \frac {x^3}{a+b (c x^n)^{\frac {1}{n}}} \, dx\) [3006]

Optimal result

Integrand size = 19, antiderivative size = 101 \[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\frac {a^2 x^4 \left (c x^n\right )^{-3/n}}{b^3}-\frac {a x^4 \left (c x^n\right )^{-2/n}}{2 b^2}+\frac {x^4 \left (c x^n\right )^{-1/n}}{3 b}-\frac {a^3 x^4 \left (c x^n\right )^{-4/n} \log \left (a+b \left (c x^n\right )^{\frac {1}{n}}\right )}{b^4} \]

[Out]

a^2*x^4/b^3/((c*x^n)^(3/n))-1/2*a*x^4/b^2/((c*x^n)^(2/n))+1/3*x^4/b/((c*x^n)^(1/n))-a^3*x^4*ln(a+b*(c*x^n)^(1/
n))/b^4/((c*x^n)^(4/n))

Rubi [A] (verified)

Time = 0.03 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {375, 45} \[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=-\frac {a^3 x^4 \left (c x^n\right )^{-4/n} \log \left (a+b \left (c x^n\right )^{\frac {1}{n}}\right )}{b^4}+\frac {a^2 x^4 \left (c x^n\right )^{-3/n}}{b^3}-\frac {a x^4 \left (c x^n\right )^{-2/n}}{2 b^2}+\frac {x^4 \left (c x^n\right )^{-1/n}}{3 b} \]

[In]

Int[x^3/(a + b*(c*x^n)^n^(-1)),x]

[Out]

(a^2*x^4)/(b^3*(c*x^n)^(3/n)) - (a*x^4)/(2*b^2*(c*x^n)^(2/n)) + x^4/(3*b*(c*x^n)^n^(-1)) - (a^3*x^4*Log[a + b*
(c*x^n)^n^(-1)])/(b^4*(c*x^n)^(4/n))

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 375

Int[((d_.)*(x_))^(m_.)*((a_) + (b_.)*((c_.)*(x_)^(q_))^(n_))^(p_.), x_Symbol] :> Dist[(d*x)^(m + 1)/(d*((c*x^q
)^(1/q))^(m + 1)), Subst[Int[x^m*(a + b*x^(n*q))^p, x], x, (c*x^q)^(1/q)], x] /; FreeQ[{a, b, c, d, m, n, p, q
}, x] && IntegerQ[n*q] && NeQ[x, (c*x^q)^(1/q)]

Rubi steps \begin{align*} \text {integral}& = \left (x^4 \left (c x^n\right )^{-4/n}\right ) \text {Subst}\left (\int \frac {x^3}{a+b x} \, dx,x,\left (c x^n\right )^{\frac {1}{n}}\right ) \\ & = \left (x^4 \left (c x^n\right )^{-4/n}\right ) \text {Subst}\left (\int \left (\frac {a^2}{b^3}-\frac {a x}{b^2}+\frac {x^2}{b}-\frac {a^3}{b^3 (a+b x)}\right ) \, dx,x,\left (c x^n\right )^{\frac {1}{n}}\right ) \\ & = \frac {a^2 x^4 \left (c x^n\right )^{-3/n}}{b^3}-\frac {a x^4 \left (c x^n\right )^{-2/n}}{2 b^2}+\frac {x^4 \left (c x^n\right )^{-1/n}}{3 b}-\frac {a^3 x^4 \left (c x^n\right )^{-4/n} \log \left (a+b \left (c x^n\right )^{\frac {1}{n}}\right )}{b^4} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.20 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.86 \[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\frac {x^4 \left (c x^n\right )^{-4/n} \left (b \left (c x^n\right )^{\frac {1}{n}} \left (6 a^2-3 a b \left (c x^n\right )^{\frac {1}{n}}+2 b^2 \left (c x^n\right )^{2/n}\right )-6 a^3 \log \left (a+b \left (c x^n\right )^{\frac {1}{n}}\right )\right )}{6 b^4} \]

[In]

Integrate[x^3/(a + b*(c*x^n)^n^(-1)),x]

[Out]

(x^4*(b*(c*x^n)^n^(-1)*(6*a^2 - 3*a*b*(c*x^n)^n^(-1) + 2*b^2*(c*x^n)^(2/n)) - 6*a^3*Log[a + b*(c*x^n)^n^(-1)])
)/(6*b^4*(c*x^n)^(4/n))

Maple [C] (warning: unable to verify)

Result contains higher order function than in optimal. Order 9 vs. order 3.

Time = 4.42 (sec) , antiderivative size = 380, normalized size of antiderivative = 3.76

method	result	size
risch	\(\frac {c^{-\frac {3}{n}} \left (x^{n}\right )^{-\frac {3}{n}} x^{3} \left (\frac {b^{2} \left (x^{n}\right )^{\frac {2}{n}} c^{\frac {2}{n}} x \,{\mathrm e}^{-\frac {i \pi \,\operatorname {csgn}\left (i c \,x^{n}\right ) \left (-\operatorname {csgn}\left (i x^{n}\right )+\operatorname {csgn}\left (i c \,x^{n}\right )\right ) \left (\operatorname {csgn}\left (i c \right )-\operatorname {csgn}\left (i c \,x^{n}\right )\right )}{2 n}}}{3}-\frac {b \,c^{\frac {1}{n}} \left (x^{n}\right )^{\frac {1}{n}} a x \,{\mathrm e}^{-\frac {i \pi \,\operatorname {csgn}\left (i c \,x^{n}\right ) \left (-\operatorname {csgn}\left (i x^{n}\right )+\operatorname {csgn}\left (i c \,x^{n}\right )\right ) \left (\operatorname {csgn}\left (i c \right )-\operatorname {csgn}\left (i c \,x^{n}\right )\right )}{n}}}{2}+a^{2} x \,{\mathrm e}^{-\frac {3 i \pi \,\operatorname {csgn}\left (i c \,x^{n}\right ) \left (-\operatorname {csgn}\left (i x^{n}\right )+\operatorname {csgn}\left (i c \,x^{n}\right )\right ) \left (\operatorname {csgn}\left (i c \right )-\operatorname {csgn}\left (i c \,x^{n}\right )\right )}{2 n}}\right )}{b^{3}}-\frac {\ln \left (b \left (x^{n}\right )^{\frac {1}{n}} c^{\frac {1}{n}} {\mathrm e}^{\frac {i \pi \,\operatorname {csgn}\left (i c \,x^{n}\right ) \left (-\operatorname {csgn}\left (i x^{n}\right )+\operatorname {csgn}\left (i c \,x^{n}\right )\right ) \left (\operatorname {csgn}\left (i c \right )-\operatorname {csgn}\left (i c \,x^{n}\right )\right )}{2 n}}+a \right ) \left (x^{n}\right )^{-\frac {1}{n}} c^{-\frac {1}{n}} a^{3} c^{-\frac {3}{n}} \left (x^{n}\right )^{-\frac {3}{n}} x^{4} {\mathrm e}^{-\frac {2 i \pi \,\operatorname {csgn}\left (i c \,x^{n}\right ) \left (-\operatorname {csgn}\left (i x^{n}\right )+\operatorname {csgn}\left (i c \,x^{n}\right )\right ) \left (\operatorname {csgn}\left (i c \right )-\operatorname {csgn}\left (i c \,x^{n}\right )\right )}{n}}}{b^{4}}\)	\(380\)

[In]

int(x^3/(a+b*(c*x^n)^(1/n)),x,method=_RETURNVERBOSE)

[Out]

1/(c^(1/n))^3/((x^n)^(1/n))^3*x^3/b^3*(1/3*b^2*((x^n)^(1/n))^2*(c^(1/n))^2*x*exp(-1/2*I*Pi*csgn(I*c*x^n)*(-csg
n(I*x^n)+csgn(I*c*x^n))*(csgn(I*c)-csgn(I*c*x^n))/n)-1/2*b*c^(1/n)*(x^n)^(1/n)*a*x*exp(-I*Pi*csgn(I*c*x^n)*(-c
sgn(I*x^n)+csgn(I*c*x^n))*(csgn(I*c)-csgn(I*c*x^n))/n)+a^2*x*exp(-3/2*I*Pi*csgn(I*c*x^n)*(-csgn(I*x^n)+csgn(I*
c*x^n))*(csgn(I*c)-csgn(I*c*x^n))/n))-ln(b*(x^n)^(1/n)*c^(1/n)*exp(1/2*I*Pi*csgn(I*c*x^n)*(-csgn(I*x^n)+csgn(I
*c*x^n))*(csgn(I*c)-csgn(I*c*x^n))/n)+a)/((x^n)^(1/n))/(c^(1/n))*a^3*c^(-3/n)*(x^n)^(-3/n)*x^4/b^4*exp(-2*I*Pi
*csgn(I*c*x^n)*(-csgn(I*x^n)+csgn(I*c*x^n))*(csgn(I*c)-csgn(I*c*x^n))/n)

Fricas [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.73 \[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\frac {2 \, b^{3} c^{\frac {3}{n}} x^{3} - 3 \, a b^{2} c^{\frac {2}{n}} x^{2} + 6 \, a^{2} b c^{\left (\frac {1}{n}\right )} x - 6 \, a^{3} \log \left (b c^{\left (\frac {1}{n}\right )} x + a\right )}{6 \, b^{4} c^{\frac {4}{n}}} \]

[In]

integrate(x^3/(a+b*(c*x^n)^(1/n)),x, algorithm="fricas")

[Out]

1/6*(2*b^3*c^(3/n)*x^3 - 3*a*b^2*c^(2/n)*x^2 + 6*a^2*b*c^(1/n)*x - 6*a^3*log(b*c^(1/n)*x + a))/(b^4*c^(4/n))

Sympy [F]

\[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\int \frac {x^{3}}{a + b \left (c x^{n}\right )^{\frac {1}{n}}}\, dx \]

[In]

integrate(x**3/(a+b*(c*x**n)**(1/n)),x)

[Out]

Integral(x**3/(a + b*(c*x**n)**(1/n)), x)

Maxima [F]

\[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\int { \frac {x^{3}}{\left (c x^{n}\right )^{\left (\frac {1}{n}\right )} b + a} \,d x } \]

[In]

integrate(x^3/(a+b*(c*x^n)^(1/n)),x, algorithm="maxima")

[Out]

integrate(x^3/((c*x^n)^(1/n)*b + a), x)

Giac [F]

\[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\int { \frac {x^{3}}{\left (c x^{n}\right )^{\left (\frac {1}{n}\right )} b + a} \,d x } \]

[In]

integrate(x^3/(a+b*(c*x^n)^(1/n)),x, algorithm="giac")

[Out]

integrate(x^3/((c*x^n)^(1/n)*b + a), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {x^3}{a+b \left (c x^n\right )^{\frac {1}{n}}} \, dx=\int \frac {x^3}{a+b\,{\left (c\,x^n\right )}^{1/n}} \,d x \]

[In]

int(x^3/(a + b*(c*x^n)^(1/n)),x)

[Out]

int(x^3/(a + b*(c*x^n)^(1/n)), x)